Thursday, January 31, 2013

some tree operations

<recursion is most common, but there is memory call overhead>
inorder: stack
preorder: dfs
postorder: stack


nonRecursivePostorder(rootNode)
  nodeStack.push(rootNode)
  while (! nodeStack.empty())
    currNode = nodeStack.peek()
    if ((currNode.left != null) and (currNode.left.visited == false))
      nodeStack.push(currNode.left)
    else 
      if ((currNode.right != null) and (currNode.right.visited == false))
        nodeStack.push(currNode.right)
      else
        print currNode.value
        currNode.visited := true
        nodeStack.pop()



stl replacement of tree:

set and map


struct ltstr
{
  bool operator()(const char* s1, const char* s2) const
  {
    return strcmp(s1, s2) < 0;
  }
};

int main()
{
  const int N = 6;
  const char* a[N] = {"isomer", "ephemeral", "prosaic", 
                      "nugatory", "artichoke", "serif"};
  const char* b[N] = {"flat", "this", "artichoke",
                      "frigate", "prosaic", "isomer"};

  set<const char*, ltstr> A(a, a + N);
  set<const char*, ltstr> B(b, b + N);
  set<const char*, ltstr> C;

  cout << "Set A: ";
  copy(A.begin(), A.end(), ostream_iterator<const char*>(cout, " "));
  cout << endl;
  cout << "Set B: ";
  copy(B.begin(), B.end(), ostream_iterator<const char*>(cout, " "));   
  cout << endl;

  cout << "Union: ";
  set_union(A.begin(), A.end(), B.begin(), B.end(),
            ostream_iterator<const char*>(cout, " "),
            ltstr());   
  cout << endl;

  cout << "Intersection: ";
  set_intersection(A.begin(), A.end(), B.begin(), B.end(),
                   ostream_iterator<const char*>(cout, " "),
                   ltstr());    
  cout << endl;

  set_difference(A.begin(), A.end(), B.begin(), B.end(),
                 inserter(C, C.begin()),
                 ltstr());
  cout << "Set C (difference of A and B): ";
  copy(C.begin(), C.end(), ostream_iterator<const char*>(cout, " "));
  cout << endl;
}

1 comment:

  1. ets are based on the abstract data structure of a binary search tree

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